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chriscalandro

i dont usually post on here but i need physics help

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MathematicS

Q.E.D



So then a class in economicS gets shortened to econS?

You're confused. The word mathematics isn't a plural but rather all encompassing. The shortened version should be just that, a simple truncation. No "S" is required.

I realize that's how people in England use it, but fuck 'em. They also drive on the wrong side of the road. ;)
quade -
The World's Most Boring Skydiver

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yeah, i used 40.

i forgot my formula sheet and my internet seems to be blocking any type of search for some reason....

thanks a lot

biomechanics has absolutely nothing to do with my major, and i am terrible at math. this class was a bad choice



Should have taken Organic
Divot your source for all things Hillbilly.
Anvil Brother 84
SCR 14192

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[shakes head and harks back to a time when Britania Ruled the Waves]
:P



That's Britannia, since you're goin' on abou' spelin'


I don't want to pick nits or pile on but I think it's harkens, not harks.:)
Also, for the OP...... your original problem refers to Force, mass and acceleration. Just pull these out of the word problem and see if you can arrange them into a recognizable formula. Sometimes doing that will get you going in the right direction.

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ok, one more for someone whose up for it...

the skip of the canadian curling team exerts a horizontal force of 14n against the 20kg rock during his delivery. at this instant the rock is sliding across the ice, and the skip is not exerting any vertical force. the coeffcient of static friction between the rock and the ice is .06 the dynamic friction is .05. what is the horizontal acceleration of the rock.

just the formula would be great...
this is the last one, i promise

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ok, one more for someone whose up for it...

the skip of the canadian curling team exerts a horizontal force of 14n against the 20kg rock during his delivery. at this instant the rock is sliding across the ice, and the skip is not exerting any vertical force. the coeffcient of static friction between the rock and the ice is .06 the dynamic friction is .05. what is the horizontal acceleration of the rock.

just the formula would be great...
this is the last one, i promise



Here's a stab at it.
resistive force = coef of friction * normal force.
normal force = mass * g
a = F(difference between resistive and applied forces)/m

I'm probably forgetting something but maybe not. Since the rock is sliding I think you use the dynamic coef. I don't think the static coef is needed.

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the static is to get the object moving
dynamic is after its moving
(it takes more energy to start movement than to continue movement)



OK...so the "skip" is not applying force continuously.
Acceleration of the rock at the instant the force is applied is (Applied force - resistive force)/m (using static coef). After that, the acceleration is negative and the dynamic coefficient is used and is simply resistive force/m.

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ok, one more for someone whose up for it...

the skip of the canadian curling team exerts a horizontal force of 14n against the 20kg rock during his delivery. at this instant the rock is sliding across the ice, and the skip is not exerting any vertical force. the coeffcient of static friction between the rock and the ice is .06 the dynamic friction is .05. what is the horizontal acceleration of the rock.

just the formula would be great...
this is the last one, i promise



Two Junior Bacon Cheeseburgers, a medium fry, and a small Frosty?
HAMMER:
Originally employed as a weapon of war, the hammer nowadays is used as a
kind of divining rod to locate the most expensive parts adjacent the
object we are trying to hit.

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