wingnut 0 #1 December 7, 2006 okay so i was taking moron math (lowest math class at school) (cuz i can't remeber how to do math since i was in high school 8 years ago) and took the final on tueday and this problem has been bugging the shit out of me, only one i wasn't sure on that it wasn't because i couldn't remebr the damn formula or something.. so here it is will write it out since i don't know how to do superscript here... [17(x squared)] minus 2x = 0 that is again [seventeen (x squared)] minus 2x equals zero.. only thing i could come up with is that x equals 0.... but for some reason i want to think i am wrong... ______________________________________ "i have no reader's digest version" Quote Share this post Link to post Share on other sites
BlueSkiesKel 0 #2 December 7, 2006 if i copied your problem right.. 17x^2 -2x=0 the first step is to factor out the x so you have x(17x-2)=0 so that means either x=0 or 17x-2=0 which means x=0 or 2/17 (yeah i'm a math geek) Quote Share this post Link to post Share on other sites
wingnut 0 #3 December 7, 2006 damn, maybe i'll get half credit... 3 points is better than none... and now that you did that i feel even dumber for not even realizing it......i keep asking myself why i picked a major that requires calc 4...... oh well ______________________________________ "i have no reader's digest version" Quote Share this post Link to post Share on other sites
BlueSkiesKel 0 #4 December 7, 2006 dont feel dumb, its ok, some people just look at numbers and it makes sense, unfortunately for some reason my brain does that just remember..first rule in solving equations..look for factoring out terms.. makes for simplifying them a lot easier good luck! Quote Share this post Link to post Share on other sites billeisele 130 #5 December 7, 2006 just wait until you get to Axiomatic Geometry, the world where lines are not straight and 2 lines can cross but not touchGive one city to the thugs so they can all live together. I vote for Chicago where they have strict gun laws. Quote Share this post Link to post Share on other sites Icon134 0 #6 December 7, 2006 Quote(cuz i can't remeber how to do math since i was in high school 8 years ago)don't feel dumb man... you gave a legit reason to not know what's going on here... Trust me I'm an engineer and when I started my graduate program a little over a year ago I walked in my Calculus review and had no idea what was going on (it had been about 6 years since my last math course...) after a year of being back in school... I can do it again... but it took a little while to get back into the groove... Livin' on the Edge... sleeping with my rigger's wife... Quote Share this post Link to post Share on other sites Butters 0 #7 December 7, 2006 Quotedamn, maybe i'll get half credit... 3 points is better than none... and now that you did that i feel even dumber for not even realizing it......i keep asking myself why i picked a major that requires calc 4...... oh well My professor started the first day of Calculus 3 with the following statement: "You will never use what you are about to learn unless you work for NASA and even then you probably won't use anything you learn." Approximately half the students dropped after that lecture and half of the remaining students failed. Good luck and remember to put the fun in functions!"That looks dangerous." Leopold Stotch Quote Share this post Link to post Share on other sites kbordson 8 #8 December 7, 2006 You should have answered "AN-2" Quote Share this post Link to post Share on other sites katiebear21 0 #9 December 7, 2006 Quoteif i copied your problem right.. 17x^2 -2x=0 the first step is to factor out the x so you have x(17x-2)=0 so that means either x=0 or 17x-2=0 which means x=0 or 2/17 (yeah i'm a math geek) x is not 0; 17x(sq) - 2x = 0 17x(sq) = 2x 17x = 2 x = 2/17 if x = 0 then you would have had 0 = -2 Katie Get your PMS glass necklace here Quote Share this post Link to post Share on other sites Butters 0 #10 December 7, 2006 QuoteQuoteif i copied your problem right.. 17x^2 -2x=0 the first step is to factor out the x so you have x(17x-2)=0 so that means either x=0 or 17x-2=0 which means x=0 or 2/17 (yeah i'm a math geek) x is not 0; 17x(sq) - 2x = 0 17x(sq) = 2x 17x = 2 x = 2/17 if x = 0 then you would have had 0 = -2 This is a joke right? "That looks dangerous." Leopold Stotch Quote Share this post Link to post Share on other sites missg8tordivr 0 #11 December 7, 2006 I concur... x=0 or x=2/17 So...maybe they will give half credit.*** F LORIDA! Quote Share this post Link to post Share on other sites wildblue 7 #12 December 7, 2006 Quotex is not 0; x can be 0 17(0^2) - 2(0) = 0 ... don't make me pull out my graphing calculator it's like incest - you're substituting convenience for quality Quote Share this post Link to post Share on other sites simplyputsi 0 #13 December 7, 2006 QuoteQuoteif i copied your problem right.. 17x^2 -2x=0 the first step is to factor out the x so you have x(17x-2)=0 so that means either x=0 or 17x-2=0 which means x=0 or 2/17 (yeah i'm a math geek) x is not 0; 17x(sq) - 2x = 0 17x(sq) = 2x 17x = 2 x = 2/17 if x = 0 then you would have had 0 = -2 You should get some sleep. You are obviously tired. The person that said something about NASA and not using it. Yup I'm that guy cept I don't work for NASA. I majored in math and took some seriously funked up classes that the teacher even said well this stuff really isn't used in life, but it's used to explain stuff in life. So when you want an explanation you ask somebody that knows math. Just don't ask me, I usually don't careSkymama's #2 stalker - Quote Share this post Link to post Share on other sites katiebear21 0 #14 December 7, 2006 Katie Get your PMS glass necklace here Quote Share this post Link to post Share on other sites Butters 0 #15 December 7, 2006 Constants: x0, y0, m, b, c (x - x0)^2 + ((m * x + b) - y0)^2 = c^2 x = ? *This equations is used to find a point on a line given a distance from another point on the line."That looks dangerous." Leopold Stotch Quote Share this post Link to post Share on other sites simplyputsi 0 #16 December 7, 2006 QuoteConstants: x0, y0, m, b, c (x - x0)^2 + ((m * x + b) - y0)^2 = c^2 x = ? I can prove to you that x does not exist. Now what do you think about that?Skymama's #2 stalker - Quote Share this post Link to post Share on other sites popsjumper 2 #17 December 7, 2006 QuoteConstants: x0, y0, m, b, c (x - x0)^2 + ((m * x + b) - y0)^2 = c^2 x = ? X = some stupid shit that I'll never use...again. My reality and yours are quite different. I think we're all Bozos on this bus. Falcon5232, SCS8170, SCSA353, POPS9398, DS239 Quote Share this post Link to post Share on other sites PLFKING 4 #18 December 7, 2006 Quoteand this problem has been bugging the shit out of me Did you hear about the constipated mathmetician ? He worked his problem out with a pencil. I think this problem has mentally constipated you. Don"When in doubt I whip it out, I got me a rock-and-roll band. It's a free-for-all." Quote Share this post Link to post Share on other sites missg8tordivr 0 #19 December 7, 2006 QuoteConstants: x0, y0, m, b, c (x - x0)^2 + ((m * x + b) - y0)^2 = c^2 x = ? 16.464 *** F LORIDA! Quote Share this post Link to post Share on other sites guppie01 0 #20 December 7, 2006 QuoteQuoteConstants: x0, y0, m, b, c (x - x0)^2 + ((m * x + b) - y0)^2 = c^2 x = ? X = some stupid shit that I'll never use...again. Can I get a AhMEN!!! g"Let's do something romantic this Saturday... how bout we bust out the restraints?" Raddest Ho this side of Jersey #1 - MISS YOU OMG, is she okay? Quote Share this post Link to post Share on other sites SpeedRacer 1 #21 December 7, 2006 why would you use the line equation? Actually you could use the following formula for any equation having this format: ax2 + bx + c = 0 x will equal: -b + or - the square root of (bsquared - 4ac) 2a In this case a = 17 b = -2 and c = 0 since c = 0 you could eliminate the "4ac" bit, so the root of bsquared is just b, but positive. x = (2 + 2 ) / 34 = 0.1176 (or 2/17) or x = (2 - 2)/ 34 = 0 Speed Racer -------------------------------------------------- Quote Share this post Link to post Share on other sites jtval 0 #22 December 7, 2006 this thread makes my balls itch. (Ok go back to your books.)My photos My Videos Quote Share this post Link to post Share on other sites jcd11235 0 #23 December 7, 2006 QuoteQuotedamn, maybe i'll get half credit... 3 points is better than none... and now that you did that i feel even dumber for not even realizing it......i keep asking myself why i picked a major that requires calc 4...... oh well My professor started the first day of Calculus 3 with the following statement: "You will never use what you are about to learn unless you work for NASA and even then you probably won't use anything you learn." Approximately half the students dropped after that lecture and half of the remaining students failed. Good luck and remember to put the fun in functions! Calc 3 was cake. It was just Calc 1 & 2 in triplicate. Math tutoring available. Only $6! per hour! First lesson: Factorials! Quote Share this post Link to post Share on other sites jcd11235 0 #24 December 7, 2006 QuoteConstants: x0, y0, m, b, c (x - x0)^2 + ((m * x + b) - y0)^2 = c^2 x = ? *This equations is used to find a point on a line given a distance from another point on the line. x = (sqrt(-b^2-2b(m*x0-y0)+c^2(m^2+1)-m^2*x0^2+2m*x0*y0-y0^2)-b*m+m*y0+x0)/(m^2+1) or x = -(sqrt(-b^2-2b(m*x0-y0)+c^2(m^2+1)-m^2*x0^2+2m*x0*y0-y0^2)+b*m-m*y0-x0)/(m^2+1) Just some old school factoring! Math tutoring available. Only $6! per hour! First lesson: Factorials! Quote Share this post Link to post Share on other sites wingnut 0 #25 December 8, 2006 well don't know if i got half credit or not, but got my grade ofr the class, a b... not what i wanted but good enough....... as long as i passed with a c or better i'm happy... just means i have to work harder next quarter to get back to a mid 3. somthing for a gpa.. need a 3.4 for autum quarter 2007 to get into the freshman honors enginnering class sequence.... ______________________________________ "i have no reader's digest version" Quote Share this post Link to post Share on other sites Join the conversation You can post now and register later. If you have an account, sign in now to post with your account. Note: Your post will require moderator approval before it will be visible. Reply to this topic... × Pasted as rich text. Paste as plain text instead Only 75 emoji are allowed. × Your link has been automatically embedded. Display as a link instead × Your previous content has been restored. 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billeisele 130 #5 December 7, 2006 just wait until you get to Axiomatic Geometry, the world where lines are not straight and 2 lines can cross but not touchGive one city to the thugs so they can all live together. I vote for Chicago where they have strict gun laws. Quote Share this post Link to post Share on other sites
Icon134 0 #6 December 7, 2006 Quote(cuz i can't remeber how to do math since i was in high school 8 years ago)don't feel dumb man... you gave a legit reason to not know what's going on here... Trust me I'm an engineer and when I started my graduate program a little over a year ago I walked in my Calculus review and had no idea what was going on (it had been about 6 years since my last math course...) after a year of being back in school... I can do it again... but it took a little while to get back into the groove... Livin' on the Edge... sleeping with my rigger's wife... Quote Share this post Link to post Share on other sites
Butters 0 #7 December 7, 2006 Quotedamn, maybe i'll get half credit... 3 points is better than none... and now that you did that i feel even dumber for not even realizing it......i keep asking myself why i picked a major that requires calc 4...... oh well My professor started the first day of Calculus 3 with the following statement: "You will never use what you are about to learn unless you work for NASA and even then you probably won't use anything you learn." Approximately half the students dropped after that lecture and half of the remaining students failed. Good luck and remember to put the fun in functions!"That looks dangerous." Leopold Stotch Quote Share this post Link to post Share on other sites
kbordson 8 #8 December 7, 2006 You should have answered "AN-2" Quote Share this post Link to post Share on other sites
katiebear21 0 #9 December 7, 2006 Quoteif i copied your problem right.. 17x^2 -2x=0 the first step is to factor out the x so you have x(17x-2)=0 so that means either x=0 or 17x-2=0 which means x=0 or 2/17 (yeah i'm a math geek) x is not 0; 17x(sq) - 2x = 0 17x(sq) = 2x 17x = 2 x = 2/17 if x = 0 then you would have had 0 = -2 Katie Get your PMS glass necklace here Quote Share this post Link to post Share on other sites
Butters 0 #10 December 7, 2006 QuoteQuoteif i copied your problem right.. 17x^2 -2x=0 the first step is to factor out the x so you have x(17x-2)=0 so that means either x=0 or 17x-2=0 which means x=0 or 2/17 (yeah i'm a math geek) x is not 0; 17x(sq) - 2x = 0 17x(sq) = 2x 17x = 2 x = 2/17 if x = 0 then you would have had 0 = -2 This is a joke right? "That looks dangerous." Leopold Stotch Quote Share this post Link to post Share on other sites
missg8tordivr 0 #11 December 7, 2006 I concur... x=0 or x=2/17 So...maybe they will give half credit.*** F LORIDA! Quote Share this post Link to post Share on other sites
wildblue 7 #12 December 7, 2006 Quotex is not 0; x can be 0 17(0^2) - 2(0) = 0 ... don't make me pull out my graphing calculator it's like incest - you're substituting convenience for quality Quote Share this post Link to post Share on other sites
simplyputsi 0 #13 December 7, 2006 QuoteQuoteif i copied your problem right.. 17x^2 -2x=0 the first step is to factor out the x so you have x(17x-2)=0 so that means either x=0 or 17x-2=0 which means x=0 or 2/17 (yeah i'm a math geek) x is not 0; 17x(sq) - 2x = 0 17x(sq) = 2x 17x = 2 x = 2/17 if x = 0 then you would have had 0 = -2 You should get some sleep. You are obviously tired. The person that said something about NASA and not using it. Yup I'm that guy cept I don't work for NASA. I majored in math and took some seriously funked up classes that the teacher even said well this stuff really isn't used in life, but it's used to explain stuff in life. So when you want an explanation you ask somebody that knows math. Just don't ask me, I usually don't careSkymama's #2 stalker - Quote Share this post Link to post Share on other sites
katiebear21 0 #14 December 7, 2006 Katie Get your PMS glass necklace here Quote Share this post Link to post Share on other sites
Butters 0 #15 December 7, 2006 Constants: x0, y0, m, b, c (x - x0)^2 + ((m * x + b) - y0)^2 = c^2 x = ? *This equations is used to find a point on a line given a distance from another point on the line."That looks dangerous." Leopold Stotch Quote Share this post Link to post Share on other sites
simplyputsi 0 #16 December 7, 2006 QuoteConstants: x0, y0, m, b, c (x - x0)^2 + ((m * x + b) - y0)^2 = c^2 x = ? I can prove to you that x does not exist. Now what do you think about that?Skymama's #2 stalker - Quote Share this post Link to post Share on other sites
popsjumper 2 #17 December 7, 2006 QuoteConstants: x0, y0, m, b, c (x - x0)^2 + ((m * x + b) - y0)^2 = c^2 x = ? X = some stupid shit that I'll never use...again. My reality and yours are quite different. I think we're all Bozos on this bus. Falcon5232, SCS8170, SCSA353, POPS9398, DS239 Quote Share this post Link to post Share on other sites
PLFKING 4 #18 December 7, 2006 Quoteand this problem has been bugging the shit out of me Did you hear about the constipated mathmetician ? He worked his problem out with a pencil. I think this problem has mentally constipated you. Don"When in doubt I whip it out, I got me a rock-and-roll band. It's a free-for-all." Quote Share this post Link to post Share on other sites
missg8tordivr 0 #19 December 7, 2006 QuoteConstants: x0, y0, m, b, c (x - x0)^2 + ((m * x + b) - y0)^2 = c^2 x = ? 16.464 *** F LORIDA! Quote Share this post Link to post Share on other sites
guppie01 0 #20 December 7, 2006 QuoteQuoteConstants: x0, y0, m, b, c (x - x0)^2 + ((m * x + b) - y0)^2 = c^2 x = ? X = some stupid shit that I'll never use...again. Can I get a AhMEN!!! g"Let's do something romantic this Saturday... how bout we bust out the restraints?" Raddest Ho this side of Jersey #1 - MISS YOU OMG, is she okay? Quote Share this post Link to post Share on other sites
SpeedRacer 1 #21 December 7, 2006 why would you use the line equation? Actually you could use the following formula for any equation having this format: ax2 + bx + c = 0 x will equal: -b + or - the square root of (bsquared - 4ac) 2a In this case a = 17 b = -2 and c = 0 since c = 0 you could eliminate the "4ac" bit, so the root of bsquared is just b, but positive. x = (2 + 2 ) / 34 = 0.1176 (or 2/17) or x = (2 - 2)/ 34 = 0 Speed Racer -------------------------------------------------- Quote Share this post Link to post Share on other sites
jtval 0 #22 December 7, 2006 this thread makes my balls itch. (Ok go back to your books.)My photos My Videos Quote Share this post Link to post Share on other sites
jcd11235 0 #23 December 7, 2006 QuoteQuotedamn, maybe i'll get half credit... 3 points is better than none... and now that you did that i feel even dumber for not even realizing it......i keep asking myself why i picked a major that requires calc 4...... oh well My professor started the first day of Calculus 3 with the following statement: "You will never use what you are about to learn unless you work for NASA and even then you probably won't use anything you learn." Approximately half the students dropped after that lecture and half of the remaining students failed. Good luck and remember to put the fun in functions! Calc 3 was cake. It was just Calc 1 & 2 in triplicate. Math tutoring available. Only $6! per hour! First lesson: Factorials! Quote Share this post Link to post Share on other sites
jcd11235 0 #24 December 7, 2006 QuoteConstants: x0, y0, m, b, c (x - x0)^2 + ((m * x + b) - y0)^2 = c^2 x = ? *This equations is used to find a point on a line given a distance from another point on the line. x = (sqrt(-b^2-2b(m*x0-y0)+c^2(m^2+1)-m^2*x0^2+2m*x0*y0-y0^2)-b*m+m*y0+x0)/(m^2+1) or x = -(sqrt(-b^2-2b(m*x0-y0)+c^2(m^2+1)-m^2*x0^2+2m*x0*y0-y0^2)+b*m-m*y0-x0)/(m^2+1) Just some old school factoring! Math tutoring available. Only $6! per hour! First lesson: Factorials! Quote Share this post Link to post Share on other sites
wingnut 0 #25 December 8, 2006 well don't know if i got half credit or not, but got my grade ofr the class, a b... not what i wanted but good enough....... as long as i passed with a c or better i'm happy... just means i have to work harder next quarter to get back to a mid 3. somthing for a gpa.. need a 3.4 for autum quarter 2007 to get into the freshman honors enginnering class sequence.... ______________________________________ "i have no reader's digest version" Quote Share this post Link to post Share on other sites
