AshDeBash 0 #26 January 17, 2006 ***Now for the quiz : How high can one count on their hands, assuming both hands are used, and they each have five fingers? Quote I believe this question has been answered It would depend on how many "states" you can put each finger into. e.g. Two states for each finger (on or off the table), you should be able to count to 2^10 (or 1024). However, if you can put your fingers into more than 2 recognisable states, this number can be increased dramatically. e.g. 3 states for each finger 3^10 (or 59049) Why the hell anyone would want to do this - I don't know!!!! Quote Share this post Link to post Share on other sites mark 107 #27 January 17, 2006 QuoteHow high can one count on their hands, assuming both hands are used, and they each have five fingers? That would be (2^10) - 1, assuming each digit has two possible positions and you start at 0. If each digit has more possible positions, then you could count higher. A finger could be fully flexed, partially extended, or fully extended to enable you to count to (3^10) - 1. You are limited by how small the extension can be and still be detectable. If you could detect 10 increments for each extension, you could count to (10^10) - 1. You could count even higher if hand position had some value: one palm (or both) toward you or away from you would increase the count by a factor of 4, or by 9 if an intermediate position had value. Also even higher if hand altitude could be assigned a value, depending on whether the hand was held up toward the ceiling, at waist level, or toward the floor. What do I win? Mark Quote Share this post Link to post Share on other sites rehmwa 2 #28 January 17, 2006 It's a lot like comparing darts and shuttlecocks. One goes farther than the other. Unless you freeze it in a block of ice. Then they go pretty much the same distance. But could you really call a shuttlecock frozen in a block of ice a 'birdie' at that point. I think not. Keebler cookies are on sale at Cub right now 10 bags for $10. ... Driving is a one dimensional activity - a monkey can do it - being proud of your driving abilities is like being proud of being able to put on pants Quote Share this post Link to post Share on other sites tso-d_chris 0 #29 January 17, 2006 QuoteThat would be (2^10) - 1, assuming each digit has two possible positions and you start at 0. You are correct, assuming two positions of the finger (up or down). You win nothing. Sorry. For Great Deals on Gear Quote Share this post Link to post Share on other sites mark 107 #30 January 17, 2006 QuoteBut could you really call a shuttlecock frozen in a block of ice a 'birdie' at that point. That depends on how high you set the par. If it's under the par, it's definitely at least a birdie. Mark Quote Share this post Link to post Share on other sites rehmwa 2 #31 January 17, 2006 QuoteQuoteBut could you really call a shuttlecock frozen in a block of ice a 'birdie' at that point. That depends on how high you set the par. If it's under the par, it's definitely at least a birdie. Mark you are so clearly my skydiving hero ... Driving is a one dimensional activity - a monkey can do it - being proud of your driving abilities is like being proud of being able to put on pants Quote Share this post Link to post Share on other sites Akey 0 #32 January 17, 2006 Number of possible arragement is 5! You will find the (! stands for factorial) button on any scientific calculator. Basically if you have 3 letters, say A, B and C they can be arranged in 3! ways. That is 3x2x1 ways. To prove it: ABC ACB BCA BAC CAB CBA i.e 6 ways. (3x2x1=6) i.e 6! I think this was the question. Therefore how many ways can you order 5 objects=5!. Therefore 5x4x3x2x1=120 ways! Quote Share this post Link to post Share on other sites JohnGraham 0 #33 January 17, 2006 QuoteI've always liked the idea of factorials but I too thought it was used to find a number of possibilities, ie, if I had five individual number and I would take the factorial of 5 to find the number of possible combinations. is this right? Somebody please enlighten me on one. [unnecessary blab]Any n distinct objects can be arranged in n! { = 1 * 2 * 3 * ... * (n-1) * n } different ways because you have n choices for the object that goes in the first place, then (n-1) choices for the object in the second place (because you've used up one object to put in the first place) then (n-2) choices for the third place and so on, until you've built up an ordered list of your n objects. (this only works if all the objects are different) So if you have four objects, say "1", "2", "3" and "4", you try to build an ordered list of them - you have four choices for the first object in the list (any of the four), three choices for the second object (any of the four less the object you put in the first position, which you can't put in the second position as well), two choices for the third object and then one choice for the last object, which makes 4*3*2*1 = 4! = 24 different possible arrangements.[/unnecessary blab] So using a factorial to find the number of possible arrangements only applies if; 1) You're trying to find out how many arrangements of n objects there are in n different spaces. 2) You aren't allowed to include duplicates - so eg [1,2,3,2] is not allowed. Quote Share this post Link to post Share on other sites kallend 2,027 #34 January 18, 2006 QuoteQuote How high can one count on their hands, assuming both hands are used, and they each have five fingers? Highest I've ever counted on my hands was 43,000ft in a Cessna Citation, but I expect it can be done higher if you find the right aircraft.... The only sure way to survive a canopy collision is not to have one. Quote Share this post Link to post Share on other sites VerticalRush 0 #35 January 18, 2006 It's just too hard to keep it simple isn't it Quote Share this post Link to post Share on other sites Prev 1 2 Next Page 2 of 2 Join the conversation You can post now and register later. If you have an account, sign in now to post with your account. Note: Your post will require moderator approval before it will be visible. Reply to this topic... × Pasted as rich text. Paste as plain text instead Only 75 emoji are allowed. × Your link has been automatically embedded. Display as a link instead × Your previous content has been restored. Clear editor × You cannot paste images directly. Upload or insert images from URL. 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mark 107 #27 January 17, 2006 QuoteHow high can one count on their hands, assuming both hands are used, and they each have five fingers? That would be (2^10) - 1, assuming each digit has two possible positions and you start at 0. If each digit has more possible positions, then you could count higher. A finger could be fully flexed, partially extended, or fully extended to enable you to count to (3^10) - 1. You are limited by how small the extension can be and still be detectable. If you could detect 10 increments for each extension, you could count to (10^10) - 1. You could count even higher if hand position had some value: one palm (or both) toward you or away from you would increase the count by a factor of 4, or by 9 if an intermediate position had value. Also even higher if hand altitude could be assigned a value, depending on whether the hand was held up toward the ceiling, at waist level, or toward the floor. What do I win? Mark Quote Share this post Link to post Share on other sites
rehmwa 2 #28 January 17, 2006 It's a lot like comparing darts and shuttlecocks. One goes farther than the other. Unless you freeze it in a block of ice. Then they go pretty much the same distance. But could you really call a shuttlecock frozen in a block of ice a 'birdie' at that point. I think not. Keebler cookies are on sale at Cub right now 10 bags for $10. ... Driving is a one dimensional activity - a monkey can do it - being proud of your driving abilities is like being proud of being able to put on pants Quote Share this post Link to post Share on other sites
tso-d_chris 0 #29 January 17, 2006 QuoteThat would be (2^10) - 1, assuming each digit has two possible positions and you start at 0. You are correct, assuming two positions of the finger (up or down). You win nothing. Sorry. For Great Deals on Gear Quote Share this post Link to post Share on other sites
mark 107 #30 January 17, 2006 QuoteBut could you really call a shuttlecock frozen in a block of ice a 'birdie' at that point. That depends on how high you set the par. If it's under the par, it's definitely at least a birdie. Mark Quote Share this post Link to post Share on other sites
rehmwa 2 #31 January 17, 2006 QuoteQuoteBut could you really call a shuttlecock frozen in a block of ice a 'birdie' at that point. That depends on how high you set the par. If it's under the par, it's definitely at least a birdie. Mark you are so clearly my skydiving hero ... Driving is a one dimensional activity - a monkey can do it - being proud of your driving abilities is like being proud of being able to put on pants Quote Share this post Link to post Share on other sites
Akey 0 #32 January 17, 2006 Number of possible arragement is 5! You will find the (! stands for factorial) button on any scientific calculator. Basically if you have 3 letters, say A, B and C they can be arranged in 3! ways. That is 3x2x1 ways. To prove it: ABC ACB BCA BAC CAB CBA i.e 6 ways. (3x2x1=6) i.e 6! I think this was the question. Therefore how many ways can you order 5 objects=5!. Therefore 5x4x3x2x1=120 ways! Quote Share this post Link to post Share on other sites
JohnGraham 0 #33 January 17, 2006 QuoteI've always liked the idea of factorials but I too thought it was used to find a number of possibilities, ie, if I had five individual number and I would take the factorial of 5 to find the number of possible combinations. is this right? Somebody please enlighten me on one. [unnecessary blab]Any n distinct objects can be arranged in n! { = 1 * 2 * 3 * ... * (n-1) * n } different ways because you have n choices for the object that goes in the first place, then (n-1) choices for the object in the second place (because you've used up one object to put in the first place) then (n-2) choices for the third place and so on, until you've built up an ordered list of your n objects. (this only works if all the objects are different) So if you have four objects, say "1", "2", "3" and "4", you try to build an ordered list of them - you have four choices for the first object in the list (any of the four), three choices for the second object (any of the four less the object you put in the first position, which you can't put in the second position as well), two choices for the third object and then one choice for the last object, which makes 4*3*2*1 = 4! = 24 different possible arrangements.[/unnecessary blab] So using a factorial to find the number of possible arrangements only applies if; 1) You're trying to find out how many arrangements of n objects there are in n different spaces. 2) You aren't allowed to include duplicates - so eg [1,2,3,2] is not allowed. Quote Share this post Link to post Share on other sites
kallend 2,027 #34 January 18, 2006 QuoteQuote How high can one count on their hands, assuming both hands are used, and they each have five fingers? Highest I've ever counted on my hands was 43,000ft in a Cessna Citation, but I expect it can be done higher if you find the right aircraft.... The only sure way to survive a canopy collision is not to have one. Quote Share this post Link to post Share on other sites VerticalRush 0 #35 January 18, 2006 It's just too hard to keep it simple isn't it Quote Share this post Link to post Share on other sites Prev 1 2 Next Page 2 of 2 Join the conversation You can post now and register later. If you have an account, sign in now to post with your account. Note: Your post will require moderator approval before it will be visible. Reply to this topic... × Pasted as rich text. Paste as plain text instead Only 75 emoji are allowed. × Your link has been automatically embedded. Display as a link instead × Your previous content has been restored. Clear editor × You cannot paste images directly. Upload or insert images from URL. Insert image from URL × Desktop Tablet Phone Submit Reply 0
VerticalRush 0 #35 January 18, 2006 It's just too hard to keep it simple isn't it Quote Share this post Link to post Share on other sites
