How does this work?!?!?!?!?!

[jumpergirl 0]

I know this is kind of old and a lot of you have probably seen this before (I know I have), but my mom just emailed this to me and it got me to thinking... how does it work?

The guys in my office and I have done this several times and it's always right. Does anyone know how it works????

http://digicc.com/fido/

[wingnut 0]

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How does this work

MAGIC!!!

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"i have no reader's digest version"

[jumpergirl 0]

That's not exactly the answer I was looking for. Thanks for playing, but spin again.

[catfishhunter 2]

Quantum Physics,I that is the right but WTF do I know about math, one of them super brainy mathmatics.

MAKE EVERY DAY COUNT
Life is Short and we never know how long we are going to have. We must live life to the fullest EVERY DAY. Everything we do should have a greater purpose.

[davedlg 0]

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Does anyone know how it works????

Whenever you subtract an jumbled number from the base number (ie. 321-123) you will get a number which the sum of the digits are factor of 9...(ie. 9,18,27, etc) by knowing the sum of the other two or three numbers in the number the program adds or subtracts as nessecary to get to a number that is a factor of 9. since a single digit cannot be higher than 9, there is only one possible answer.

[Slappie 9]

That's really neat.. Got me on how that works though. Maybe some of the brainiaks around here can answer it.

"Find out just what any people will quietly submit to and you have found out the exact measure of injustice and wrong which will be imposed upon them."

[jumpergirl 0]

That sounds reasonable.

[jazzjumper 0]

It works via brute force, meaning when you input your 1 or 2 numbers, it grinds out the possibilities computationally. Are you looking for a mathematical proof or a general "this is how?"

Frankly, it seems to work as long as you have at least 2 different numbers and don't pick a 0 when you are circling a number. Now the 0 does work most of the time, but I can break it with the correct numbers.

So, if you key in the numbers 1,2; that means you could have a number, 1-9 (remember you can't use a zero) in the computation. So, you have 27 possible pairs of numbers that you are looking for that match the following criteria:

x - y = z,
where z = 12a, or 1a2, or a12 and a is the missing number,
where the digits in x are the same digits in y, in a different order.

Now, with a 4 digit number, you have a total of 24 possible combinations with different numbers, 18 with 2 like numbers, and 12 with 2 like pairs of numbers.

After that, it's just a matter of brute force computing to figure out the correct missing number.

Not magic, just a counting problem. Who would think counting could be so difficult.

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[jumpergirl 0]

That's what I was looking for! Now I get it.

This is one of those things that you learn in high school, but forget. I think it was one of those, "I'm going to learn this until I have a test on it then forget it because I'll never need to know this in real life."

[MarkM 0]

Okay, don't think it's working for me:

Pick a 3 or 4 digit number: 7599
Jumble it: 5799
Subtract one from other: 1500
Circle the 5
Jumble the remaining numbers: 010

It says it's 8, but it isn't.

[catfishhunter 2]

thats because your total is not 1500 try your math again... it is 1800

MAKE EVERY DAY COUNT
Life is Short and we never know how long we are going to have. We must live life to the fullest EVERY DAY. Everything we do should have a greater purpose.

[larsrulz 0]

Quote

Okay, don't think it's working for me:

Pick a 3 or 4 digit number: 7599
Jumble it: 5799
Subtract one from other: 1500
Circle the 5
Jumble the remaining numbers: 010

It says it's 8, but it isn't.

7599-5799 is 1800

I got a strong urge to fly, but I got no where to fly to. -PF

[jtval 0]

Quote

Quote

Does anyone know how it works????

Whenever you subtract an jumbled number from the base number (ie. 321-123) you will get a number which the sum of the digits are factor of 9...(ie. 9,18,27, etc) by knowing the sum of the other two or three numbers in the number the program adds or subtracts as nessecary to get to a number that is a factor of 9. since a single digit cannot be higher than 9, there is only one possible answer.

sounds good but if you add more then 4 numbers the ( thing is out. the eqaution changes.

I tried it with a 6 digit number then the common Number is 8. it must be programmed for each equation depending on the amount of digits.

EDIT: now that I look again the magic # isnt 8. but Im sure it works on the same prinicple

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[MarkM 0]

Ahh yeah, *cough cough*

[davedlg 0]

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sounds good but if you add more then 4 numbers the ( thing is out. the eqaution changes.

I tried it with a 6 digit number then the common Number is 8. it must be programmed for each equation depending on the amount of digits.

Hmm. Every Number I've tried (as high as 8 digits) always comes up with a number divisible by nine. Subtract the the two numbers, add up the digits, divide by nine and you will ALWYAS get an integer. Give me an example if you can find one that doesnt.