QuickDraw 0 #26 June 9, 2003 I'm a piscean its in my nature to waste time. -- Hope you don't die. -- I'm fucking winning Quote Share this post Link to post Share on other sites
mjosparky 4 #27 June 9, 2003 Just what to you interview people for? SparkyMy idea of a fair fight is clubbing baby seals Quote Share this post Link to post Share on other sites
sfc 1 #28 June 9, 2003 i blame Archimedes, it's all his fault. Quote Share this post Link to post Share on other sites
PhillyKev 0 #29 June 9, 2003 Right thinking....but it's a "very heavy lead anchor" so the mass acting on the boat would displace more than the volume of the anchor itself. Quote Share this post Link to post Share on other sites
Schroeder 0 #30 June 9, 2003 but that depends on the size of the boat, a larger boat would distribute more and displace less. Quote Share this post Link to post Share on other sites
sfc 1 #31 June 9, 2003 it can't be too heavy or the boat would sink, it would displace it's own weight in water while it was in the boat, this would make the water level rise. When it was resting on the bottom it would not, this would make the boat rise and the water level fall. Quote Share this post Link to post Share on other sites
sfc 1 #32 June 9, 2003 it only depends on the weight of the anchor, the size of the boat makes no difference Quote Share this post Link to post Share on other sites
Schroeder 0 #33 June 9, 2003 Quote it can't be too heavy or the boat would sink, it would displace it's own weight in water while it was in the boat, this would make the water level rise. When it was resting on the bottom it would not, this would make the boat rise and the water level fall. nope, the volume of the anchor will still displace, whether it's on the bottom or not. If I ventured in the slipstream; Between the via-ducts of your dreams.......could you find me? Quote Share this post Link to post Share on other sites
PhillyKev 0 #34 June 9, 2003 Sort of. Weight doesn't displace water. Volume does. But the weight of the anchor acting on the boat would cause a larger volume of the boat to be pulled beneath the surface than the volume of the anchor itself when it is in the water. So, when the anchor is in the boat, the water level is higher than when it is sitting on the bottom. But if the anchor didn't reach the bottom, you still have the same amount of displacement from the boat, but you've now added the volume of the anchor itself. Quote Share this post Link to post Share on other sites
sfc 1 #35 June 9, 2003 this is what archimedes found out, he was the one that ran naked through the streets when he found out how to catch people nicking the kings gold. Archimedes' principle that states that a body immersed in a fluid is buoyed up by a force equal to the weight of the displaced fluid. The principle applies to both floating and submerged bodies and to all fluids, i.e., liquids and gases. It explains not only the buoyancy of ships and other vessels in water but also the rise of a balloon in the air and the apparent loss of weight of objects underwater. In determining whether a given body will float in a given fluid, both weight and volume must be considered; that is, the relative density, or weight per unit of volume, of the body compared to the fluid determines the buoyant force. If the body is less dense than the fluid, it will float or, in the case of a balloon, it will rise. If the body is denser than the fluid, it will sink. Relative density also determines the proportion of a floating body that will be submerged in a fluid. If the body is two thirds as dense as the fluid, then two thirds of its volume will be submerged, displacing in the process a volume of fluid whose weight is equal to the entire weight of the body. In the case of a submerged body, the apparent weight of the body is equal to its weight in air less the weight of an equal volume of fluid. The fluid most often encountered in applications of Archimedes' principle is water, and the specific gravity of a substance is a convenient measure of its relative density compared to water. In calculating the buoyant force on a body, however, one must also take into account the shape and position of the body. A steel rowboat placed on end into the water will sink because the density of steel is much greater than that of water. However, in its normal, keel-down position, the effective volume of the boat includes all the air inside it, so that its average density is then less than that of water, and as a result it will float. Quote Share this post Link to post Share on other sites
Schroeder 0 #36 June 9, 2003 Quoteit only depends on the weight of the anchor, the size of the boat makes no difference yes it does Quote Share this post Link to post Share on other sites
sfc 1 #37 June 9, 2003 i have to disagree, when the wankers is in the boat it displaces it's weight in water, regardless of how big the boat is. The only thing different about the big boat is that you can but more wankers in it before it sinks, but you'd have to bre pretty f*ckin stupid to put so many wankers in a boat so that it would sink. Quote Share this post Link to post Share on other sites
PhillyKev 0 #38 June 9, 2003 Yep....I agree with you. But...if the boat weighs X and anchor weighs Y, with the anchor in it, it's going to displace Z amount of water. If you throw the anchor in and it sinks to the bottom, you will only displace the amount of water proportional to the bouyancy of the boat at weight X, not X+Y, so the water level will fall. But...if you throw the anchor in and it doesn't reach the bottom, the weight of the boat has not changed, it is still X+Y. In addition, you have the volume of the anchor itself which is no longer outside of the water but instead is now in it. While the specific size of the boat may not matter, the shape of it certainly would. A narrower boat with a deep keel will contain less air and therefore have a higher density, be less bouyant and displace more water. Quote Share this post Link to post Share on other sites
Schroeder 0 #39 June 9, 2003 although, earlier, you said for the brainiacs to keep out, I think now is about right to call them back. Quote Share this post Link to post Share on other sites
sfc 1 #40 June 9, 2003 Drop the anchor in the water, if it does not touch the bottom it will displace the same amount of water as when it was in the boat, things always weigh less under water. that's it I'm all physicst out... Quote Share this post Link to post Share on other sites
flyhi 24 #41 June 9, 2003 QuoteArchimedes' principle that states that a body immersed in a fluid is buoyed up by a force equal to the weight of the displaced fluid. Actually, I think Archimedes' principle states that when a body is immersed in a fluid, the phone will ring.Shit happens. And it usually happens because of physics. Quote Share this post Link to post Share on other sites
PhillyKev 0 #42 June 9, 2003 The size of the boat would make a difference according to the principal he posted. The displacement is based on the density of the boat. The density is comprised of the weight of the materials plus the weight of the air contained within divided by the volume. As you increase the size of the boat the density will decrease because a larger proportion of the volume will be air. Therefore, since density has decreased, the boat will be more buoyant and less of the boat will be submerged. It may be a bigger boat, but as you increase it's size the volume of air increases at a higher factor than the surface area (and so density decreases at a higher factor than the surface area increases). So, a larger boat would displace less water given the same cargo weight. Quote Share this post Link to post Share on other sites
sfc 1 #43 June 9, 2003 no no no no no it just wouldn't sink as far into the water. Think of it this way, the weight of the boat pushes down into the water, the water pushes back with exactly the same amount of wieght(force), if the weight of boat was more than the force of the water pushing it back up, the boat would sink. The amount of force that the water pushes back at the boat is equal to the amount of water rises. So it doesn't matter how big the boat is, if it weighs the same the level of the water will change the same. and that's really it... Quote Share this post Link to post Share on other sites
Schroeder 0 #44 June 9, 2003 I rule. Thanks for rationalizing my intuition. Quote Share this post Link to post Share on other sites
PhillyKev 0 #45 June 9, 2003 QuoteSo it doesn't matter how big the boat is, if it weighs the same the level of the water will change the same. If the boat is bigger, hence more materials, and more air within it, it doesn't weigh the same. However, it is less dense. And it is less dense in greater proportion than its surface area, so it will displace less. Quote Share this post Link to post Share on other sites
sfc 1 #46 June 9, 2003 I give up... now you know why I gave up teaching, i was never any good at explaining things Quote Share this post Link to post Share on other sites
Jib 0 #47 June 9, 2003 QuoteI declare this off limit to Kallend or BillVon or any other mechanical engineer/physics professor typies See what happens when you ban the professor types? -------------------------------------------------- the depth of his depravity sickens me. -- Jerry Falwell, People v. Larry Flynt Quote Share this post Link to post Share on other sites
PhillyKev 0 #48 June 9, 2003 Yeah...but the thread would be dead already if they came in here and explained it. Quote Share this post Link to post Share on other sites
Cornholio 0 #49 June 9, 2003 Oh LOOKY!!! Butthead: Whoa! Burritos for breakfast! Beavis: Yeah! Yeah! Cool! bellyflier on the dz.com hybrid record jump Quote Share this post Link to post Share on other sites
Cornholio 0 #50 June 9, 2003 **** SHINY THINGS ***** Butthead: Whoa! Burritos for breakfast! Beavis: Yeah! Yeah! Cool! bellyflier on the dz.com hybrid record jump Quote Share this post Link to post Share on other sites
