marks 0 #51 July 28, 2006 QuoteI think the question is what is the terminal velocity of you and your canopy. BINGO! lol.... you can also accelerate "you and your canopy" by using the rears. i'm not going to get into that one. Quote Share this post Link to post Share on other sites
raymod2 1 #52 July 28, 2006 Quoteif your car goes 0-60 in 6 sec, and you start at 10 mph, in 5 sec you are going 60. if you start at 40 mph in 2 sec you are going 60. This analogy is flawed. In a car acceleration is not constant. It decreases as velocity increases. QuoteThe canopy can only create lift perpendicular to the top skin. No, lift is perpendicular to the direction of flight (by definition). It is definitely NOT perpendicular to the wing since that would mean your angle of attack is zero in which case you are producing no lift at all. Quote The "tightness" i.e. the radius, of your turn will determine the riser pressure. No, the angle of attack and airspeed will determine riser pressure. Quote Share this post Link to post Share on other sites
superstu 0 #53 July 28, 2006 what's the difference if you reach 60mph starting at 0mph or at 10mph? maybe a better question is: are you more likely to hit 60mph starting from 0mph, or from 10mph? (i am not saying 60mph is our terminal velocity) either way, a pilots goal is usually to hit the begining of their swoop with as much speed as possibleSlip Stream Air Sports Do not go softly, do not go quietly, never back down Quote Share this post Link to post Share on other sites
dlee 0 #54 August 3, 2006 QuoteQuoteif your car goes 0-60 in 6 sec, and you start at 10 mph, in 5 sec you are going 60. if you start at 40 mph in 2 sec you are going 60. This analogy is flawed. In a car acceleration is not constant. It decreases as velocity increases. perhaps the analogy was not the best. the point is if you start at a higher speed it takes less time to get to your final speed. the relationship is not directly linear. QuoteQuoteThe canopy can only create lift perpendicular to the top skin. No, lift is perpendicular to the direction of flight (by definition). It is definitely NOT perpendicular to the wing since that would mean your angle of attack is zero in which case you are producing no lift at all. you need to be more specific, your statement is ambiguous. both down and left are also perpendicular to the direction of flight. when your canopy goes to a high roll angle, as when we start a turn lift is no longer directly opposing gravity. if you want to be totally honest about it the top skin is curved so the idea of perpendicular is non-sensical. again you are missing the point. for more on lift interested parties should see: http://www.aa.washington.edu/faculty/eberhardt/lift.htm QuoteQuote The "tightness" i.e. the radius, of your turn will determine the riser pressure. No, the angle of attack and airspeed will determine riser pressure. finally, riser pressure is just the tension in the lines. in flat stable flight, this is precisely 1 g regardless of airspeed or angle of attack. once you have an angular acceleration, recovery arc, a 270, whatever, this can increase, but only then. if you let up from half brakes the canopy will surge ahead and the lines go a little slack as you and the canopy are not well connected. Quote Share this post Link to post Share on other sites
cessna54tango 0 #55 August 3, 2006 Hey guys this is a very good discussion. i have tried both methods and see the pros and cons of both techniques. i do braked approach 270s, you guys have posted some good points. Quote Share this post Link to post Share on other sites
